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Match List-I with List-II

List-IList-II
(A) Line : x=2y+1=z−1x = 2y + 1 = z - 1(I) Crosses xzxz plane at (1, 0, 1)
(B) Line : x+1=2y+1=zx + 1 = 2y + 1 = z(II) Crosses xzxz plane at (0, 0, 1)
(C) Line : x−1=2y=z+1x - 1 = 2y = z + 1(III) Crosses xzxz plane at (1, 0, -1)
(D) Line : x−1=2y=z−1x - 1 = 2y = z - 1(IV) Crosses xzxz plane at (1, 0, 2)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

The xz plane is where y=0y = 0. To find where each line crosses the xz plane, set y=0y = 0 and solve for xx and zz.


Line: x=2y+1=z−1x = 2y + 1 = z - 1

Setting y=0y = 0:

x=2(0)+1x = 2(0) + 1

x=1x = 1

From x=z−1x = z - 1:

1=z−11 = z - 1

z=2z = 2

The line crosses the xz plane at (1,0,2)(1, 0, 2), which corresponds to (IV).


Line: x+1=2y+1=zx + 1 = 2y + 1 = z

Setting y=0y = 0:

x+1=2(0)+1x + 1 = 2(0) + 1

x+1=1x + 1 = 1

x=0x = 0

From x+1=zx + 1 = z:

0+1=z0 + 1 = z

z=1z = 1

The line crosses the xz plane at (0,0,1)(0, 0, 1), which corresponds to (II).


Line: x−1=2y=z+1x - 1 = 2y = z + 1

Setting y=0y = 0:

x−1=2(0)x - 1 = 2(0)

x−1=0x - 1 = 0

x=1x = 1

From x−1=z+1x - 1 = z + 1:

1−1=z+11 - 1 = z + 1

0=z+10 = z + 1

z=−1z = -1

The line crosses the xz plane at (1,0,−1)(1, 0, -1), which corresponds to (III).


Line: x−1=2y=z−1x - 1 = 2y = z - 1

Setting y=0y = 0:

x−1=2(0)x - 1 = 2(0)

x−1=0x - 1 = 0

x=1x = 1

From x−1=z−1x - 1 = z - 1:

1−1=z−11 - 1 = z - 1

0=z−10 = z - 1

z=1z = 1

The line crosses the xz plane at (1,0,1)(1, 0, 1), which corresponds to (I).


(A) - (IV), (B) - (II), (C) - (III), (D) - (I)

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