CUET Mathematics - For independent events A_1, A_2, A_3, ..., A_n if P(A_i) = 1/i+1, i = 1, 2, 3, ..., n, then the probability that none of the events occur is: | PYQs + Solutions

CUET Mathematics 2025 27 May Shift 1

Algebra

Medium

applied

$\frac{n}{n+1}$

$\frac{n-1}{n+1}$

$\frac{1}{n+1}$

$\frac{n-1}{2(n+1)}$

✅ Correct Option: 3

Related questions:

CUET Mathematics 2024 Slot 1

Let $X$ denote the number of hours you play during a randomly selected day. The probability that $X$ can take values $x$ has the following form, where $c$ is some constant.

$\mathrm{P}(\mathrm{X}=\mathrm{x})=\left\{\begin{array}{lll} 0.1, & \text { if } \mathrm{x}=0 \\ \mathrm{cx}, & \text { if } \mathrm{x}=1 \text { or } \mathrm{x}=2 \\ \mathrm{c}(5-\mathrm{x}), & \text { if } \mathrm{x}=3 \text { or } \mathrm{x}=4 \\ 0, & \text { otherwise } \end{array}\right.$

Match List-I with List-II :

List-I	List-II
(A) $c$	(I) 0.75
(B) $P(X \leq 2)$	(II) 0.3
(C) $P(X = 2)$	(III) 0.55
(D) $P(X \geq 2)$	(IV) 0.15

30 May Shift 1

A die is tossed once. If the random variable X is defined as $X = \begin{cases} 1, & \text{if the die result in an odd number} \\ -1, & \text{if the die result in an even number} \end{cases}$ , then the variance of X is

3 June Shift 1

The probability that a leap year selected at random will have 53 Mondays is

CUET Mathematics 2025 27 May Shift 1 PYQs

Keyboard Shortcuts