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If x,y∈Rx, y \in \mathbb{R} then match List-I with List-II

List-IList-II
(A) ∣x∣<∣y∣\vert x\vert < \vert y\vert (I) iff x2>y2x^2 > y^2
(B) ∣x∣>∣y∣\vert x\vert > \vert y\vert (II) iff x2≤y2x^2 \le y^2
(C) ∣x∣≤∣y∣\vert x\vert \le \vert y\vert (III) iff x2<y2x^2 < y^2
(D) ∣x∣≥∣y∣\vert x\vert \ge \vert y\vert (IV) iff x2≥y2x^2 \ge y^2

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

For any real number aa, ∣a∣2=a2|a|^2 = a^2.

Since absolute values are always non-negative, both sides of any inequality involving ∣x∣|x| and ∣y∣|y| can be safely squared without flipping the inequality sign.


(A) ∣x∣<∣y∣|x| < |y|

∣x∣2<∣y∣2|x|^2 < |y|^2

x2<y2x^2 < y^2

(A)→(III)(A) \rightarrow (III)


(B) ∣x∣>∣y∣|x| > |y|

∣x∣2>∣y∣2|x|^2 > |y|^2

x2>y2x^2 > y^2

(B)→(I)(B) \rightarrow (I)


(C) ∣x∣≤∣y∣|x| \leq |y|

∣x∣2≤∣y∣2|x|^2 \leq |y|^2

x2≤y2x^2 \leq y^2

(C)→(II)(C) \rightarrow (II)


(D) ∣x∣≥∣y∣|x| \geq |y|

∣x∣2≥∣y∣2|x|^2 \geq |y|^2

x2≥y2x^2 \geq y^2

(D)→(IV)(D) \rightarrow (IV)


(A)→(III)(A) \rightarrow (III), (B)→(I)(B) \rightarrow (I), (C)→(II)(C) \rightarrow (II), (D)→(IV)(D) \rightarrow (IV)

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