Algebra > Inequalities

Medium

applied

If $x, y \in \mathbb{R}$ then match List-I with List-II | List-I | List-II | | --- | --- | | (A) $\vert x\vert < \vert y\vert $ | (I) iff $x^2 > y^2$ | | (B) $\vert x\vert > \vert y\vert $ | (II) iff $x^2 \le y^2$ | | (C) $\vert x\vert \le \vert y\vert $ | (III) iff $x^2 < y^2$ | | (D) $\vert x\vert \ge \vert y\vert $ | (IV) iff $x^2 \ge y^2$ | Choose the correct answer from the options given below:

(A) - (III), (B) - (II), (C) - (I), (D) - (IV)

(A) - (III), (B) - (I), (C) - (II), (D) - (IV)

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

(A) - (III), (B) - (II), (C) - (IV), (D) - (I)

✅ Correct Option: 2

Related questions:

2026: 15th May Shift 1

Which of the following are correct?

A. If $|x-5|<2$ , then $x \in (3,7)$

B. If $|x-1|<4$ , then $x \in (-3,5)$

C. If $|x-2|<6$ , then $x \in (4,8)$

D. If $|x-4|<1$ , then $x \in (-3,5)$

Choose the correct answer from the options given below:

2023: 15 June Shift 2

Match List - I with List - II.

List - I	List - II
(A) The solution set of the inequality $-5x > 3$ , $x \in R$ , is	(I) $\left[\frac{20}{7}, \infty\right)$
(B) The solution set of the inequality is, $\frac{-7x}{4} \leq -5$ , $x \in R$ is,	(II) $\left[\frac{4}{7}, \infty\right)$
(C) The solution set of the inequality $7x - 4 \geq 0$ , $x \in R$ is,	(III) $\left(-\infty, \frac{7}{5}\right)$
(D) The solution set of the inequality $9x - 4 < 4x + 3$ , $x \in R$ is,	(IV) $\left(-\infty, -\frac{3}{5}\right)$

Choose the correct answer from the options given below :

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The solution to the inequality $-12 < \frac{2x-1}{3} < 12$ is

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The solution set of the inequation $|2x - 3| ≤ 4$ is

2026: 12th May Shift 2

The solution set of the inequation $|8x-7|\le\dfrac{2}{3}$ is

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The solution set $\{x: x \in R, 3x-2 < x+2 \le 2x+6\}$ (Where $R$ is set of real numbers) is :

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