Skip to main contentSkip to solution

Ram had invested Rs. 15,000 in a mutual fund and the value of the investment at the time of redemption was Rs. 25,000. If the compound annual growth rate (CAGR) is 8.88%, then the number of years for which Ram has invested the amount is:

[Given: log⁡1.089≈0.0370\log 1.089 \approx 0.0370 and log⁡1.667≈0.2220\log 1.667 \approx 0.2220]

Solution

✅ Correct Option: 1

The initial investment is Rs. 15,000 and the final value is Rs. 25,000. The CAGR is 8.88% per year.

The compound annual growth rate formula is:

A=P(1+r)nA = P(1 + r)^n

where AA is the final amount, PP is the initial amount, rr is the rate, and nn is the number of years.


Substituting the values:

25,000=15,000×(1+0.0888)n25,000 = 15,000 × (1 + 0.0888)^n

25,000=15,000×(1.0888)n25,000 = 15,000 × (1.0888)^n


Dividing both sides by 15,000:

25,00015,000=(1.0888)n\dfrac{25,000}{15,000} = (1.0888)^n

53=(1.0888)n\dfrac{5}{3} = (1.0888)^n

1.667=(1.0888)n1.667 = (1.0888)^n


Taking logarithm on both sides:

log⁡(1.667)=log⁡(1.0888)n\log(1.667) = \log(1.0888)^n

log⁡(1.667)=n×log⁡(1.0888)\log(1.667) = n × \log(1.0888)


Since 1.0888≈1.0891.0888 \approx 1.089, using the given values:

0.2220=n×0.03700.2220 = n × 0.0370

n=0.22200.0370n = \dfrac{0.2220}{0.0370}

n=6n = 6

Therefore, Ram invested for 6 years.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question