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The number of all possible matrices of order 2×22 \times2 with each entry 0,10, 1 or 22 are.

Solution

✅ Correct Option: 2

A 2×2 matrix has 4 positions arranged in 2 rows and 2 columns:

[a  b]
[c  d]

There are 4 entries to fill.


Each entry can be filled with 0, 1, or 2.

This gives 3 choices for each entry.


The choices for each entry are independent:

Entry aa: 3 choices

Entry bb: 3 choices

Entry cc: 3 choices

Entry dd: 3 choices


Total number of matrices =3×3×3×3= 3 \times 3 \times 3 \times 3

=34= 3^4

=81= 81


For an m×nm \times n matrix with kk choices per entry:

Total matrices =km×n= k^{m \times n}

Here: k=3k = 3, m=2m = 2, n=2n = 2

Total matrices =32×2=34=81= 3^{2 \times 2} = 3^4 = 81

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