(1/_e x - 1/(_e x)^2)dx is equal to Option 1: x/_e x + c; c is an arbitrary constant Option 2: 1/_e x + c; c is an arbitrary constant Option 3: x/(_e x)^2 + c; c is an arbitrary constant Option 4: _e x/x + c; c is an arbitrary constant

The answer is 'x/_e x + c; c is an arbitrary constant'. View full solution:

(1/_e x - 1/(_e x)^2)dx is equal to

x/_e x + c; c is an arbitrary constant

1/_e x + c; c is an arbitrary constant

x/(_e x)^2 + c; c is an arbitrary constant

Calculus > Integrals

Medium

core

$\frac{x}{\log_e x} + c$ ; c is an arbitrary constant

$\frac{1}{\log_e x} + c$ ; c is an arbitrary constant

$\frac{x}{(\log_e x)^2} + c$ ; c is an arbitrary constant

$\frac{\log_e x}{x} + c$ ; c is an arbitrary constant

✅ Correct Option: 1

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