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If A and B are symmetric matrices of the same order, then which one of the following is true?

Solution

✅ Correct Option: 4

A symmetric matrix satisfies AT=AA^T = A (the matrix equals its transpose).

A skew-symmetric matrix satisfies AT=−AA^T = -A (transpose gives the negative).

Key properties:

(A+B)T=AT+BT(A + B)^T = A^T + B^T

(AB)T=BTAT(AB)^T = B^T A^T (order reverses)


Given that AA and BB are both symmetric matrices:

AT=AA^T = A

BT=BB^T = B


Testing A+BA+B:

(A+B)T=AT+BT(A+B)^T = A^T + B^T

=A+B= A + B

Since (A+B)T=(A+B)(A+B)^T = (A+B), this is symmetric, not skew-symmetric.


Testing A−BA-B:

(A−B)T=AT−BT(A-B)^T = A^T - B^T

=A−B= A - B

Since (A−B)T=(A−B)(A-B)^T = (A-B), this is symmetric, not skew-symmetric.


Testing AB−BAAB-BA:

(AB−BA)T=(AB)T−(BA)T(AB-BA)^T = (AB)^T - (BA)^T

=BTAT−ATBT= B^T A^T - A^T B^T

=BA−AB= BA - AB

=−(AB−BA)= -(AB - BA)

Since (AB−BA)T=−(AB−BA)(AB-BA)^T = -(AB-BA), this is skew-symmetric, not symmetric.


Testing AB+BAAB+BA:

(AB+BA)T=(AB)T+(BA)T(AB+BA)^T = (AB)^T + (BA)^T

=BTAT+ATBT= B^T A^T + A^T B^T

=BA+AB= BA + AB

=AB+BA= AB + BA

Since (AB+BA)T=(AB+BA)(AB+BA)^T = (AB+BA), this is symmetric.


Therefore, AB+BAAB+BA is a symmetric matrix.

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