CUET Mathematics 2022 6 Aug Shift 2Algebra > Easy000333−1-1−1−3-3−3✅ Correct Option: 4Related questions:3 June Shift 2If a⃗\vec{a}a is any vector, then ∣a⃗×i^∣2+∣a⃗×j^∣2+∣a⃗×k^∣2|\vec{a} \times \hat{i}|^2 + |\vec{a} \times \hat{j}|^2 + |\vec{a} \times \hat{k}|^2∣a×i^∣2+∣a×j^∣2+∣a×k^∣2 is equal to22 May Shift 1Let a⃗=i^+2j^+3k^\vec{a} = \hat{i} + 2\hat{j} + 3\hat{k}a=i^+2j^+3k^ and b⃗=−2i^+3j^−4k^\vec{b} = -2\hat{i} + 3\hat{j} - 4\hat{k}b=−2i^+3j^−4k^, then which of the following statements are correct? (A) ∣a⃗∣=14|\vec{a}| = \sqrt{14}∣a∣=14 (B) ∣b⃗∣=29|\vec{b}| = 29∣b∣=29 (C) a⃗⋅b⃗=8\vec{a} \cdot \vec{b} = 8a⋅b=8 (D) Angle between a⃗\vec{a}a and b⃗\vec{b}b is cos−1(−8406)\cos^{-1}\left(\frac{-8}{\sqrt{406}}\right)cos−1(406−8) Choose the correct answer from the options given below:19 May Shift 1If a⃗=3i^−6j⃗+k^\vec{a} = 3\hat{i} - 6\vec{j} + \hat{k}a=3i^−6j+k^ and b⃗=2i^−4j⃗+λk^\vec{b} = 2\hat{i} - 4\vec{j} + \lambda\hat{k}b=2i^−4j+λk^ are such that a⃗∥b⃗\vec{a} \parallel \vec{b}a∥b, then 3λ+2=3\lambda + 2 =3λ+2=