Let X be a discrete random variable and probability distribution X is

X	$-1$	0	1
P(X)	$\frac{1}{2}$	$\frac{1}{5}$	$\frac{3}{10}$

Then E(X) is equal to :

A die is thrown thrice. If the first throw is a four, then the chance of getting 11 as total sum, is

A die is rolled. If the outcome is an odd number, then the probability that the number is prime, is:

Three bags contain a number of red and white balls as follows:

Bag I: 3 red balls

Bag II: 2 red balls and 1 white ball

Bag III: 3 white balls

The probability that bag $i$ will be chosen, and a ball is selected from it is $\frac{i}{6}, i=1,2,3$. The probability that a red ball is selected is equal to:

A coin is tossed K times. If the probability of getting $3$ heads is equal to the probability of getting $7$ heads, then the probability of getting $8$ tails is :

A man speaks the truth 8 out of 10 times. A die is tossed. He reports that it was 5. What is the probability that it was actually 5?

A and B throw a die alternatively till one of them gets a number more than 4 and wins the game. Then the probability of winning the game by B, if A starts first :