If curve represented by differential equation x dy/dx + y = e^x passes through (1, 1), then y(-1) is : Option 1: e Option 2: e - 1 Option 3: e^2 - (e + 1) Option 4: e^2 - (e + 1)/e

The answer is 'e^2 - (e + 1)/e'. View full solution:

CUET Mathematics - If curve represented by differential equation x dy/dx + y = e^x passes through (1, 1), then y(-1) is : | PYQs + Solutions

CUET Mathematics 2022 7 Aug Shift 2

Calculus

Medium

$e$

$e - 1$

$e^2 - (e + 1)$

$\frac{e^2 - (e + 1)}{e}$

✅ Correct Option: 4

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Match List-I with List-II

List-I	List-II
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(A) $\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^2 = e^{\frac{dy}{dx}} + 1$	(I) Order = 1, Degree = 2
(B) $\left(\frac{d^2y}{dx^2}\right)^2 + 4\left(\frac{dy}{dx}\right)^3 = e^y - 1$	(II) Order = 2, Degree = 1
(C) $3\left(\frac{dy}{dx}\right) + 4y + e^y = \frac{dx}{dy}$	(III) Order = 2, Degree = 2
(D) $\frac{d^2y}{dx^2} + 3\left(\frac{dy}{dx}\right) = \left(e^y + \frac{dy}{dx}\right)^2$	(IV) Order = 2, Degree = Not defined

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