Match List - I with List - II. | | List - I (Two given vector) | | List - II (Projection of a on b) | |---|---|---|---| | (A) | a = i - j, b = i + j | (I) | 2sqrt(5) | | (B) | a = i + j, b = 2i - k | (II) | 0 | | (C) | a = j + k, b = i + k | (III) | sqrt(2) | | (D) | a = 2i + 3j, b = i - k | (IV) | 1sqrt(2) | Choose the correct answer from the options given below :

Question

Option 1: (A) - (II), (B) - (I), (C) - (IV), (D) - (III)

Option 2: (A) - (I), (B) - (II), (C) - (III), (D) - (IV)

Option 3: (A) - (III), (B) - (I), (C) - (II), (D) - (IV)

Option 4: (A) - (IV), (B) - (III), (C) - (I), (D) - (II)

AfterBoards · Accepted Answer

The answer is '(A) - (II), (B) - (I), (C) - (IV), (D) - (III)'. View full solution:

List-I	List-II
(A) The vectors $\lambda\hat{i}$ $+ \hat{j} + 2\hat{k}$ and $\vec{i} + \lambda\hat{j} + \hat{k}$ are perpendicular if λ is equal to	(I) 1
(B) The vectors $3\hat{i} + 6\hat{j} - \hat{k}$ and $2\hat{i} + 4\hat{j} - \lambda\hat{k}$ are collinear if λ is equal to	(II) -1
(C) The number of vectors of unit-length which are perpendicular to both the vectors $\vec{a}$ = $\hat{i} + \hat{j} + 2\hat{k}$ and $\vec{b}$ = $3\hat{i} - \hat{j} + 5\hat{k}$ is	(III) 2/3
(D) If $\lvert \vec{a} \rvert = 1$ and $\vec{a} + \vec{b} = \vec{0}$ , then $\lvert \vec{b} \rvert$ is equal to	(IV) 2

CUET Mathematics 2022 7 Aug Shift 2 PYQs

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