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If y=xxy = x^x, then value of dydx\frac{dy}{dx} at x=2x = 2 is :

Solution

✅ Correct Option: 2

Take logarithm: ln⁡y=xln⁡x\ln y = x \ln x.

Differentiate: 1ydydx=ln⁡x+1\frac{1}{y}\frac{dy}{dx} = \ln x + 1.

So dydx=xx(1+ln⁡x)\frac{dy}{dx} = x^x (1 + \ln x).

At x=2x = 2: dydx=22(1+log⁡2)=4(1+log⁡2)\frac{dy}{dx} = 2^2 (1 + \log 2) = 4(1 + \log 2).

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