Skip to main contentSkip to solution

The value of ∫π/2π11+cot⁡xdx\int_{\pi/2}^{\pi} \frac{1}{1 + \cot x} dx is equal to:

Solution

✅ Correct Option: 2

I=∫π/2πsin⁡xsin⁡x+cos⁡xdxI = \int_{\pi/2}^{\pi} \frac{\sin x}{\sin x + \cos x} dx. Using the property x→(3π/2−x)x \to (3\pi/2 - x): I=∫π/2πcos⁡xcos⁡x+sin⁡xdxI = \int_{\pi/2}^{\pi} \frac{\cos x}{\cos x + \sin x} dx. Adding: 2I=∫π/2π1 dx=π/22I = \int_{\pi/2}^{\pi} 1 \, dx = \pi/2. So I=π/4I = \pi/4.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question