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The values of xx and yy in the equation 2[x14−3]+3[−212y−2]=[25143]2\begin{bmatrix} x & 1 \\ 4 & -3 \end{bmatrix} + 3\begin{bmatrix} -2 & 1 \\ 2 & y-2 \end{bmatrix} = \begin{bmatrix} 2 & 5 \\ 14 & 3 \end{bmatrix} are respectively:

Solution

✅ Correct Option: 3

Equating element (1,1)(1,1): 2x−6=22x - 6 = 2, so x=4x = 4. Equating element (2,2)(2,2): −6+3(y−2)=3-6 + 3(y-2) = 3, giving 3(y−2)=93(y-2) = 9, so y=5y = 5.

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