Skip to main contentSkip to solution

If ∣a⃗∣=∣b⃗∣=∣a⃗+b⃗∣=1|\vec{a}| = |\vec{b}| = |\vec{a} + \vec{b}| = 1, then ∣a⃗−b⃗∣|\vec{a} - \vec{b}| is equal to:

Solution

✅ Correct Option: 4

∣a⃗+b⃗∣2=∣a⃗∣2+∣b⃗∣2+2a⃗⋅b⃗=1|\vec{a}+\vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 + 2\vec{a}\cdot\vec{b} = 1 gives a⃗⋅b⃗=−1/2\vec{a}\cdot\vec{b} = -1/2. Then ∣a⃗−b⃗∣2=1+1−2(−1/2)=3|\vec{a}-\vec{b}|^2 = 1 + 1 - 2(-1/2) = 3, so ∣a⃗−b⃗∣=3|\vec{a}-\vec{b}| = \sqrt{3}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question