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Match List I with List II

List I (Functions)List II (Principal value branches)
A. f(x)=cos⁡−1xf(x) = \cos^{-1} xI. [0,π][0, \pi]
B. f(x)=tan⁡−1xf(x) = \tan^{-1} xII. [0,π]−{π2}[0, \pi] - \left\{\frac{\pi}{2}\right\}
C. f(x)=cosec−1xf(x) = \text{cosec}^{-1} xIII. [−π2,π2]−{0}\left[-\frac{\pi}{2}, \frac{\pi}{2}\right] - \{0\}
D. f(x)=sec⁡−1xf(x) = \sec^{-1} xIV. (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Standard principal value ranges: cos⁡−1:[0,π]\cos^{-1}: [0, \pi] (I); tan⁡−1:(−π/2,π/2)\tan^{-1}: (-\pi/2, \pi/2) (IV); csc⁡−1:[−π/2,π/2]−{0}\csc^{-1}: [-\pi/2, \pi/2] - \{0\} (III); sec⁡−1:[0,π]−{π/2}\sec^{-1}: [0, \pi] - \{\pi/2\} (II). So A-I, B-IV, C-III, D-II.

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