vmatrix a+b & 1 & 0 \\ a^2-b^2 & a-b & 1 \\ a^3+b^3 & a^2+b^2+ab & a^2-b^2 vmatrix = Option 1: 0 Option 2: -2ab(a+b) Option 3: 1 Option 4: 2ab(a-b)

The answer is '-2ab(a+b)'. View full solution:

CUET Mathematics - vmatrix a+b & 1 & 0 \\ a^2-b^2 & a-b & 1 \\ a^3+b^3 & a^2+b^2+ab & a^2-b^2 vmatrix = | PYQs + Solutions

CUET Mathematics 2022 16 July Shift 2

Algebra

Hard

$-2ab(a+b)$

$2ab(a-b)$

✅ Correct Option: 2

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CUET Mathematics 2022 16 July Shift 2 PYQs

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