JIPMAT 2025 (QA) - 40 men can complete a work in 48 days. 64 men started and did the same work for x days. After x days, 32 men increased, so, the remaining work is completed in 162/3 days, then the value of x is | PYQs + Solutions | AfterBoards
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JIPMAT 2025

Arithmetic
>
Time & Work

Medium

40 men can complete a work in 48 days. 64 men started and did the same work for x days. After x days, 32 men increased, so, the remaining work is completed in 162316\frac{2}{3} days, then the value of xx is

✅ Correct Option: 1
Given: 4040 men can complete the work in 4848 days \newline Hence, Total work =40×48=1920=40 \times 48=1920 units.
1. 6464 men worked for x days \newline Work done =64×x=64x=64 \times x=64x units.
2. After x days, 3232 more men are added \newline Thus, the New workforce =64+32=96=64+32=96 men
Remaining work completed in 503\frac{50}{3} days \newline Work done =96×503=1600=96 \times \frac{50}{3}=1600 units.
Total Work: 64x+1600=192064x + 1600 = 1920 \newline 64x=32064x = 320 \newline x=5x = 5
Hence, the correct option is Option 1.

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