9:{"metadata":[["$","title","0",{"children":"JIPMAT 2025 (QA) - Which of the following statements is/are correct? A. If 2^x = 3^y = 6^-z, then 1/x + 1/y + 1/z = 0 B. (243)^0.16 x (9)^0.1 = 0.3 C. If 3.105 x 10^P = 0.00239 + 0.000715, then P = -3 | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined It is best to first check the (B) statement from the given options. B. (243)^0.16 (9)^0.1 = 0.3 LHS = (3)^5 0.16 (3)^2 0.1 = 3^(0.80) 3^(0.20) = 3^1 = 3 Thus, B is an incorrect statement. Hence, the only possib<= option is Option 4.

A. If 2^x = 3^y = 6^-z, then 1/x + 1/y + 1/z = 0 Given: 2^x=3^y=6^-z Let: 2^x=3^y=6^-z=k (say) Now take logs: - From 2^x=k, we >=t x= _2 k - From 3^y=k, we >=t y= _3 k - From 6^-z=k, take log: -z= _6 k z=- _6 k Now evaluate: 1/x+1/y+1/z=1 _2 k+1 _3 k+1- _6 k Use chan>= of base: 1 _b k= _k b So: = _k 2+ _k 3- _k 6= _k(2 3/6)= _k(1)=0

C. 3.105 10^P=0.00239+0.000715=0.003105 Thus, 3.105 10^P=0.003105 10^P=0.003105/3.105=10^-3 P=-3"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"JIPMAT,QA,Algebra,Linear Equations"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"JIPMAT 2025 (QA) - Which of the following statements is/are correct? A. If 2^x = 3^y = 6^-z, then 1/x + 1/y + 1/z = 0 B. (243)^0.16 x (9)^0.1 = 0.3 C. If 3.105 x 10^P = 0.00239 + 0.000715, then P = -3 | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined It is best to first check the (B) statement from the given options. B. (243)^0.16 (9)^0.1 = 0.3 LHS = (3)^5 0.16 (3)^2 0.1 = 3^(0.80) 3^(0.20) = 3^1 = 3 Thus, B is an incorrect statement. Hence, the only possib<= option is Option 4.

C. 3.105 10^P=0.00239+0.000715=0.003105 Thus, 3.105 10^P=0.003105 10^P=0.003105/3.105=10^-3 P=-3"}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/ipmat-jipmat-past-year-questions/jipmat-2025/QA/9"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IPMAT Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20IPMAT%20JIPMAT%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"JIPMAT 2025 (QA) - Which of the following statements is/are correct? A. If 2^x = 3^y = 6^-z, then 1/x + 1/y + 1/z = 0 B. (243)^0.16 x (9)^0.1 = 0.3 C. If 3.105 x 10^P = 0.00239 + 0.000715, then P = -3 | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined It is best to first check the (B) statement from the given options. B. (243)^0.16 (9)^0.1 = 0.3 LHS = (3)^5 0.16 (3)^2 0.1 = 3^(0.80) 3^(0.20) = 3^1 = 3 Thus, B is an incorrect statement. Hence, the only possib<= option is Option 4.

C. 3.105 10^P=0.00239+0.000715=0.003105 Thus, 3.105 10^P=0.003105 10^P=0.003105/3.105=10^-3 P=-3"}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21"],"error":null,"digest":"$undefined"}

JIPMAT 2025 (QA) PYQs

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