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JIPMAT 2025 (QA) PYQs

JIPMAT 2025

Geometry
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Trigonometry

Easy

Two ships are sailing in the sea on the two sides of a lighthouse. The angles of elevation of the top of the lighthouse as observed from two ships are 30° and 45°, respectively. If the lighthouse is 100 m high, the distance between two ships is approximately:

Correct Option: 3
Let Ship A and Ship B have the angle of elevation 4545^\circ and 3030^\circ, respectively.
Let their distance from the lighthouse be xx and yy respectively.
We know, height of lighthouse =100= 100 meters
For xx: \newline tan(45)=OppositesideAdjacentSide\tan (45^\circ) = \frac{Opposite side}{Adjacent Side} \newline 1=100x1= \frac{100}{x} \newline x=100x = 100 meters
For yy: \newline tan(30)=OppositesideAdjacentSide\tan (30^\circ) = \frac{Opposite side}{Adjacent Side} \newline 13=100y\frac{1}{\sqrt3}= \frac{100}{y} \newline y=100×3y = 100\times \sqrt3 \newline y=100×1.732y = 100\times 1.732 \newline y=173.2y = 173.2 meters
Hence, distance between the two ships =x+y=100+173=273= x + y = 100 + 173 = 273 meters.
Thus, the correct option is Option 3.

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