JIPMAT 2025 (QA) - Consider the following statements, which of them is/are correct? A. If the height of cylinder is doubled, the area of curved surface is doubled. B. If the radius of a hemispherical solid is doubled, its total surface area becomes fourfold. C. If a hemisphere and cone have equal bases and equal heights, then the ratio of curved surface area is sqrt(2):1. | PYQs + Solutions | AfterBoards
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JIPMAT 2025 (QA) PYQs

JIPMAT 2025

Geometry
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Solids

Hard

Consider the following statements, which of them is/are correct?
A. If the height of cylinder is doubled, the area of curved surface is doubled. \newline B. If the radius of a hemispherical solid is doubled, its total surface area becomes fourfold. \newline C. If a hemisphere and cone have equal bases and equal heights, then the ratio of curved surface area is 2:1\sqrt{2}:1.

Correct Option: 3
A. If the height of cylinder is doubled, the area of curved surface is doubled. \newline We know, Curved Surface Area of Cylinder =2πrh = 2 \pi r h \newline If height doubles, i.e. H=2hH = 2h, Curved Surface Area of Cylinder =2πrH=4πrh=2 \pi r H = 4\pi r h \newline Thus, statement A is true.
B. If the radius of a hemispherical solid is doubled, its total surface area becomes fourfold. \newline We know that the total surface area of a hemisphere =3πr2= 3\pi r^2 \newline If the radius doubles, i.e., R=2rR = 2r, the total surface area of hemisphere =3πR2=3π(2r)2=12πr2= 3 \pi R^2 = 3 \pi (2r)^2 = 12 \pi r^2 \newline Thus, statement B is true.
C. If a hemisphere and a cone have equal bases and heights, then the ratio of curved surface area is 2:1\sqrt{2}:1. \newline Let rr be the radius of the hemisphere. \newline Since the cone and the hemisphere have equal bases and heights, the base and height of the cone are rr and r2\frac{r}{2}
Thus, the slant line of the cone, say l=r2+(r2)2=r2+r24=5r2l = \sqrt{r^2 + (\frac{r}{2})^2}= \sqrt{r^2 + \frac{r^2}{4}} = \frac{\sqrt{5}r }{2}
Curved surface area of Hemisphere =2πr2=2 \pi r^2 \newline Curved surface area of Cone =πrl=5πr22= \pi r l = \frac{\sqrt{5} \pi r^2 }{2}
Thus, the ratio of curved surface area is 4:54: \sqrt5
Hence, the correct option is Option 2

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