A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the beginning and 100 more after 35 days and completes the work in stipulated time. If he had not engaged the additional men, how many days behind schedule would it be finished?

Given below are two statements:

Statement (I):

4 boys and 8 girls completed 1/3 of work in 5 days. After that 3 boys and 3 girls increased, and they completed another 1/3 of work in 3 days. If the remaining work is to be completed in 2 days, then the number of girls that should be increased is 32.

Statement (II):

The ratio of time taken by A and C to do a work is 1:2 respectively. B is 166 (2/3)% more efficient than C. Time taken by A to complete 6% of work is 6 days.

Then, the time taken by B and C together to complete the whole work is 54 (6/11) days.

In light of the above statements, choose the most appropriate answer from the options given below.

If A can do 1/4 of a work in 3 days and B can do 1/6 of the same work in 4 days, how much will A get if both work together and are paid Rs. 180 in total?

4 men and 6 women finish a job in 8 days, while 3 men and 7 women finish it in 10 days. In how many days will 10 women finish it?

A is $40 \%$ less efficient than $B$ who can do the same work in $20 \%$ less time than $C$. If $A$ and B together can complete $80 \%$ work in 12 days, then in how many days $60 \%$ work can be completed by $\mathrm{B}$ and $\mathrm{C}$ together ?

40 men can complete a work in 48 days. 64 men started and did the same work for $x$ days. After $x$ days, 32 men increased, so, the remaining work is completed in $16\frac{2}{3}$ days, then the value of $x$ is

A and B can do a piece of work in 40 days and 50 days, respectively. Both begin doing the work together but after certain time A leaves. Then, B finishes the remaining work in 20 days. After how many days did A leave?