JIPMAT 2025 (QA) - A speaks truth in 75% cases and B in 80% of the cases. In what percentage of cases are they likely to contradict each other, in narrating the same incident? | PYQs + Solutions | AfterBoards
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JIPMAT 2025 (QA) PYQs

JIPMAT 2025

Modern Math
>
Probability

Medium

A speaks truth in 75% cases and B in 80% of the cases. In what percentage of cases are they likely to contradict each other, in narrating the same incident?

Correct Option: 3
There will be two cases:
1) A speaks the truth and B lies \newline 2) A lies and B speaks the truth.
Hence,
[75%×(10080)%]+[(10075)%×80%]\Rightarrow [75\% \times (100-80)\%]+[(100-75)\%\times80\%]
75×20+25×8010000=35001000=35100=35%\Rightarrow \dfrac{75\times20+25\times80}{10000}=\dfrac{3500}{1000}=\dfrac{35}{100}=35\%

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