JIPMAT 2025 (QA) - Three numbers A, B and C are such that A is 40% less than B, and C is 40% of the sum of A and B. The difference between A and B is what percentage of C? | PYQs + Solutions | AfterBoards
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JIPMAT 2025 (QA) PYQs

JIPMAT 2025

Arithmetic
>
Percentages

Medium

Three numbers A, B and C are such that A is 40% less than B, and C is 40% of the sum of A and B. The difference between A and B is what percentage of C?

Correct Option: 3
Given: \newline 1. A is 40%40 \% less than BB \newline 2. C is 40%40 \% of the sum of AA and BB
We need to find: what percentage of CC is the difference between AA and BB ?
Let's express these relationships mathematically: \newline A=0.6B( since A is 40% less than B)C=0.4(A+B)( since C is 40% of the sum of A and B)\begin{aligned} & A=0.6 B(\text { since } A \text { is } 40 \% \text { less than } B) \\ & C=0.4(A+B)(\text { since } C \text { is } 40 \% \text { of the sum of } A \text { and } B) \end{aligned}
Substituting A=0.6BA =0.6 B into the expression for CC : \newline C=0.4(0.6B+B)=0.4(1.6B)=0.64BC=0.4(0.6 B+B)=0.4(1.6 B)=0.64 B
The difference between AA and BB is: \newline BA=B0.6 B=0.4 B\mathrm{B}-\mathrm{A}=\mathrm{B}-0.6 \mathrm{~B}=0.4 \mathrm{~B}
As a percentage of C : \newline BAC×100%=0.4B0.64B×100%=0.40.64×100%=58×100%=62.5%\dfrac{B-A}{C} \times 100 \%=\dfrac{0.4 B}{0.64 B} \times 100 \%=\dfrac{0.4}{0.64} \times 100 \%=\dfrac{5}{8} \times 100 \%=62.5 \%
Therefore, the difference between A and B is 62.5%62.5 \% of C . \newline Hence, the correct option is Option 3.

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