9:{"metadata":[["$","title","0",{"children":"JIPMAT 2025 (QA) - Arrange the following in descending order based on their perimeters: A. A square with an area of 36 sq. cm. B. An equilateral triangle with a side of 9 cm. C. A rectangle with 10 cm as length and 40 sq. cm as area. D. A circle with radius of 4 cm. | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined A arrow To find the perimeter of square, we need to find the <=ngth of side first. Area = (Side)^2 = 36 sq. cm. Side = 6 cm. Perimeter = 4 Side =24 cm. B arrow Perimeter of equilateral triang<= is 3 Side Perimeter = 3 9 = 27 cm. C arrow We need to find breadth of the rectang<= first. Area = Length Breadth = 10 Breadth = 40 sq. cm. Breadth = 4 cm. Perimeter = 2(l+b) = 2(10+4) = 28 cm. D arrow Perimeter of circ<= is 2 r Perimeter = 2 227 4 = 25.14 cm. (approx) Perimeters in descending order arrow C > B > D > A"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"JIPMAT,QA,Geometry,Polygons"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"JIPMAT 2025 (QA) - Arrange the following in descending order based on their perimeters: A. A square with an area of 36 sq. cm. B. An equilateral triangle with a side of 9 cm. C. A rectangle with 10 cm as length and 40 sq. cm as area. D. A circle with radius of 4 cm. | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined A arrow To find the perimeter of square, we need to find the <=ngth of side first. Area = (Side)^2 = 36 sq. cm. Side = 6 cm. Perimeter = 4 Side =24 cm. B arrow Perimeter of equilateral triang<= is 3 Side Perimeter = 3 9 = 27 cm. C arrow We need to find breadth of the rectang<= first. Area = Length Breadth = 10 Breadth = 40 sq. cm. Breadth = 4 cm. Perimeter = 2(l+b) = 2(10+4) = 28 cm. D arrow Perimeter of circ<= is 2 r Perimeter = 2 227 4 = 25.14 cm. (approx) Perimeters in descending order arrow C > B > D > A"}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/ipmat-jipmat-past-year-questions/jipmat-2025/QA/22"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | IPMAT Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20IPMAT%20JIPMAT%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"JIPMAT 2025 (QA) - Arrange the following in descending order based on their perimeters: A. A square with an area of 36 sq. cm. B. An equilateral triangle with a side of 9 cm. C. A rectangle with 10 cm as length and 40 sq. cm as area. D. A circle with radius of 4 cm. | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined A arrow To find the perimeter of square, we need to find the <=ngth of side first. Area = (Side)^2 = 36 sq. cm. Side = 6 cm. Perimeter = 4 Side =24 cm. B arrow Perimeter of equilateral triang<= is 3 Side Perimeter = 3 9 = 27 cm. C arrow We need to find breadth of the rectang<= first. Area = Length Breadth = 10 Breadth = 40 sq. cm. Breadth = 4 cm. Perimeter = 2(l+b) = 2(10+4) = 28 cm. D arrow Perimeter of circ<= is 2 r Perimeter = 2 227 4 = 25.14 cm. (approx) Perimeters in descending order arrow C > B > D > A"}],"$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e","$L1f","$L20","$L21"],"error":null,"digest":"$undefined"}

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