JIPMAT 2025 (QA) - Arrange the following in descending order based on their perimeters: A. A square with an area of 36 sq. cm. B. An equilateral triangle with a side of 9 cm. C. A rectangle with 10 cm as length and 40 sq. cm as area. D. A circle with radius of 4 cm. | PYQs + Solutions | AfterBoards
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JIPMAT 2025

Geometry
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Polygons

Medium

Arrange the following in descending order based on their perimeters:
A. A square with an area of 36 sq. cm. \newline B. An equilateral triangle with a side of 9 cm. \newline C. A rectangle with 10 cm as length and 40 sq. cm as area. \newline D. A circle with radius of 4 cm.

✅ Correct Option: 4
A →\rightarrow To find the perimeter of square, we need to find the length of side first. \newline Area == (Side)2^2 =36= 36 sq. cm. \newline Side =6= 6 cm. \newline Perimeter =4= 4 ×\times Side =24=24 cm.
B →\rightarrow Perimeter of equilateral triangle is 33 ×\times Side \newline Perimeter =3×9=27= 3 \times 9 = 27 cm.
C →\rightarrow We need to find breadth of the rectangle first. \newline Area == Length ×\times Breadth =10= 10 ×\times Breadth =40= 40 sq. cm. \newline Breadth =4= 4 cm. \newline Perimeter =2(l+b)=2(10+4)=28= 2(l+b) = 2(10+4) = 28 cm.
D →\rightarrow Perimeter of circle is 2πr2\pi r \newline Perimeter =2×227×4=25.14= 2 \times \dfrac{22}{7} \times 4 = 25.14 cm. (approx)\text{(approx)}
Perimeters in descending order →\rightarrow C > B > D > A

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JIPMAT 2025

The cost of fencing of an equilateral triangular park and a square park is the same. If the area of the triangular park is 16316\sqrt{3} m2^2, then the length of the diagonal of the square park is :

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