JIPMAT 2023 (QA) - <p>Amicable numbers are a pair of distinct natural numbers (a, b) such that the sum of the proper divisors of a equals b and the sum of the proper divisors of b equals a. Given that (220, y) is a pair of amicable numbers, y equals:</p> | PYQs + Solutions | AfterBoards
Skip to main contentSkip to question navigationSkip to solution
IPMAT Indore Free Mocks Topic Tests

JIPMAT 2023 (QA) PYQs

View all IPMAT/JIPMAT PYQs →
Collection of AfterBoards IPMAT JIPMAT Past Year Papers with Solutions

JIPMAT 2023

Number System
>
Miscellaneous

Medium

Amicable numbers are a pair of distinct natural numbers (a, b) such that the sum of the proper divisors of a equals b and the sum of the proper divisors of b equals a. Given that (220, y) is a pair of amicable numbers, y equals:

Correct Option: 2
Let's find all proper divisors of 220: \newline →\rightarrow Proper divisors are all positive divisors excluding the number itself \newline →\rightarrow Factors of 220 = 1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 220 \newline →\rightarrow Proper divisors of 220 = 1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110 \newline →\rightarrow Sum of proper divisors of 220 = 284
No need to check other options since we found our answer.
Therefore, y = 284.

Related questions:

JIPMAT 2022

Given below are two statements:
Statement I : The sum of exponents of prime factors in the prime factorization of 392 is 5.
Statement II : The decimal representation 1323×5\frac{13}{2^3 \times 5} will terminate after 2 decimal places.
In the light of the above statements, choose the correct answer from the options given below:

JIPMAT 2023

Given below are two statements:

Statement (I): The difference, the sum, and the product of two numbers are in the ratio 1: 5: 12. The product of the two numbers is 18.

Statement (II): The last digit in the decimal representation of 291 is 6.

In light of the above statements, choose the most appropriate answer from the options given below.

JIPMAT 2023

The expression 2x3 + ax2 + bx + 3, where a and b are constants, has a factor of x-1 and leaves a remainder of 15 when divided by x + 2. Then, (a, b) =

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question