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Match List-I with List-II

List-I (Functions)List-II (Range, principal value)
(A) sin⁡−1x\sin^{-1}x(I) [0,π]−{π2}[0,\pi]-\left\{\dfrac{\pi}{2}\right\}
(B) tan⁡−1x\tan^{-1}x(II) [−π2,π2]−{0}\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right]-\{0\}
(C) cosec−1xcosec^{-1}x(III) [−π2,π2]\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right]
(D) sec⁡−1x\sec^{-1}x(IV) (−π2,π2)\left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Principal value branches: sin⁡−1x\sin^{-1}x has the closed interval [−π2,π2]\left[-\dfrac{\pi}{2},\dfrac{\pi}{2}\right]; tan⁡−1x\tan^{-1}x has the open interval; cosec−1xcosec^{-1}x is the sine branch with 00 removed; sec⁡−1x\sec^{-1}x is [0,π][0,\pi] with π2\dfrac{\pi}{2} removed.

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