Match List-I with List-II, List-I, List-II, (A) The solution set of the inequation 3x-6≤ 0 is, (I) (3,∞), (B) The solution set of the inequation -5x+20 35 is, (IV) (4,∞), Choose the correct answer from the options given below: Option 1: (A) - (II), (B) - (IV), (C) - (I), (D) - (III) Option 2: (A) - (I), (B) - (II), (C) - (III), (D) - (IV) Option 3: (A) - (IV), (B) - (II), (C) - (III), (D) - (I) Option 4: (A) - (III), (B) - (IV), (C) - (II), (D) - (I)

Answer: (A) - (III), (B) - (IV), (C) - (II), (D) - (I). Solution: (A) 3x≤6 x≤2, i.e. (-∞,2], (III). (B) -5x 4, i.e. (4,∞), (IV). (C) 3x≥9 x≥3, i.e. [3,∞), (II). (D) 8x>24 x>3, i.e. (3,∞), (I).

Algebra

Inequalities

Easy

applied

Match List-I with List-II

List-I List-II
(A) The solution set of the inequation $3x-6\le 0$ is (I) $(3,\infty)$
(B) The solution set of the inequation $-5x+20<0$ is (II) $[3,\infty)$
(C) The solution set of the inequation $3x-9\ge 0$ is (III) $(-\infty,2]$
(D) The solution set of the inequation $8x+11>35$ is (IV) $(4,\infty)$

Choose the correct answer from the options given below:

List-I	List-II
(A) The solution set of the inequation $3x-6\le 0$ is	(I) $(3,\infty)$
(B) The solution set of the inequation $-5x+20<0$ is	(II) $[3,\infty)$
(C) The solution set of the inequation $3x-9\ge 0$ is	(III) $(-\infty,2]$
(D) The solution set of the inequation $8x+11>35$ is	(IV) $(4,\infty)$

(A) - (II), (B) - (IV), (C) - (I), (D) - (III)

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

(A) - (IV), (B) - (II), (C) - (III), (D) - (I)

(A) - (III), (B) - (IV), (C) - (II), (D) - (I)

✅ Correct Option: 4

(A) $3x\le6\Rightarrow x\le2$ , i.e. $(-\infty,2]$ , (III).

(B) $-5x<-20\Rightarrow x>4$ , i.e. $(4,\infty)$ , (IV).

(D) $8x>24\Rightarrow x>3$ , i.e. $(3,\infty)$ , (I).

2025: 15 May Shift 2

The solution set of $6 \leq -3(2x - 4) < 12$ , $x \in R$ is:

2025: 21 May Shift 2

If a, b, c are positive real numbers, then the least value of $(a+b+c)(ab+bc+ca)$ is:

2025: 27 May Shift 1

If $x, y \in \mathbb{R}$ then match List-I with List-II

List-I	List-II
(A) $\vert x\vert < \vert y\vert$	(I) iff $x^2 > y^2$
(B) $\vert x\vert > \vert y\vert$	(II) iff $x^2 \le y^2$
(C) $\vert x\vert \le \vert y\vert$	(III) iff $x^2 < y^2$
(D) $\vert x\vert \ge \vert y\vert$	(IV) iff $x^2 \ge y^2$

Choose the correct answer from the options given below:

2026: 29 May Shift 2

The solution to the inequality $-12 < \frac{2x-1}{3} < 12$ is

2025: 19 May Shift 1

Match List-I with List-II

List-I	List-II
(Inequality)	(Solution Set)
---	---
(A) $2x - 3 < x + 2 \le 3x + 5, x \in \mathbb{R}$	(I) $x \in (-1, \infty)$
(B) $\vert 2x + 3\vert < 7, x \in \mathbb{R}$	(II) $x \in (-\infty, 120]$
(C) $\frac{1}{2}\left(\frac{3}{5}x + 4\right) \ge \frac{1}{3}(x - 6), x \in \mathbb{R}$	(III) $x \in (-5, 2)$
(D) $\frac{\vert x + 1\vert }{x + 1} > 0, x \in \mathbb{R} - \{-1\}$	(IV) $x \in \left[-\frac{3}{2}, 5\right)$

Choose the correct answer from the options given below:

2025: 22 May Shift 1

If $\frac{1}{x^2} - \frac{1}{x} > 0$ , then $x$ lies in the interval

Solution

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