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The side of an equilateral triangle is increasing at the rate of 2 cm/sec. The rate at which the area of the triangle is increasing, when the side of the triangle is 5 cm, is

Solution

✅ Correct Option: 2

For side aa, area A=34a2A=\frac{\sqrt3}{4}a^2, so dAdt=32adadt\frac{dA}{dt}=\frac{\sqrt3}{2}a\frac{da}{dt}.

With a=5a=5 and dadt=2\frac{da}{dt}=2: dAdt=32(5)(2)=53\frac{dA}{dt}=\frac{\sqrt3}{2}(5)(2)=5\sqrt3 cm2^2/sec.

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