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Match List-I with List-II

List-IList-II
(A) Mean of a normal variate X is 12 and standard deviation is 4, then the Z-score of data point 20 is(I) 1
(B) If X is Poisson variate such that P(X=1) = 2P(X=2), then the mean of X is(II) 8
(C) In a binomial distribution, if mean is 5 and variance is 4, then the number of trials is(III) 2
(D) In a binomial distribution, if n = 20 and q = 0.6, then its mean is(IV) 25

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

(A) Z=20−124=2Z=\frac{20-12}{4}=2, (III).

(B) λe−λ=2⋅λ2e−λ2⇒λ=1\lambda e^{-\lambda}=2\cdot\frac{\lambda^2e^{-\lambda}}{2}\Rightarrow\lambda=1, (I).

(C) np=5np=5, npq=4⇒q=0.8npq=4\Rightarrow q=0.8, p=0.2p=0.2, n=25n=25, (IV).

(D) p=1−0.6=0.4p=1-0.6=0.4, mean =20(0.4)=8=20(0.4)=8, (II).

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