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In a printing press of a publication house, there is a small chance 11000\frac{1}{1000} for any typing error in 20 pages, then the number of pages containing no error in printing two volumes of an Encyclopedia containing total 10000 pages are:

[Given: e−0.02=0.9802e^{-0.02}=0.9802]

Solution

✅ Correct Option: 3

For a block of 20 pages, λ=20×11000=0.02\lambda=20\times\frac{1}{1000}=0.02, so P(no error)=e−0.02=0.9802P(\text{no error})=e^{-0.02}=0.9802.

10000 pages form 500 such blocks; error-free blocks =500×0.9802=490.1=500\times0.9802=490.1, i.e. about 490×20=9802490\times20=9802 pages.

Note: The stated chance applies per block of 20 pages, and we scale the Poisson result back to a page count.

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