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If the following table represents the three yearly moving averages of a data, then the value of a+b+c+d3\frac{a+b+c+d}{3} is-

YearValue3-yearly moving average
12
2a4
36b
487
5c9
612d
711

Solution

✅ Correct Option: 2

Each moving average is the mean of three consecutive values.

2+a+63=4⇒a=4\frac{2+a+6}{3}=4\Rightarrow a=4; b=4+6+83=6b=\frac{4+6+8}{3}=6; 6+8+c3=7⇒c=7\frac{6+8+c}{3}=7\Rightarrow c=7; d=7+12+113=10d=\frac{7+12+11}{3}=10.

So a+b+c+d3=273=9\frac{a+b+c+d}{3}=\frac{27}{3}=9.

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