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The area bounded by the curve y2=2xy^2 = 2x, yy-axis and the line y=1y=1, is

Solution

✅ Correct Option: 4

Integrate with respect to yy using x=y22x=\frac{y^2}{2}.

Area =∫01y22dy=[y36]01=16=\int_0^1\frac{y^2}{2}dy=\left[\frac{y^3}{6}\right]_0^1=\frac16 square units.

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