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If A and B are invertible matrices of the same order, then

Match List-I with List-II

List-I (Determinant)List-II (Equal to)
(A) ∣A−1B∣\left\vert A^{-1}B \right\vert(I) 1∣A∣∣B∣\dfrac{1}{\left\vert A \right\vert \left\vert B \right\vert}
(B) ∣AB−1∣\left\vert AB^{-1} \right\vert(II) ∣B∣∣A∣\dfrac{\left\vert B \right\vert}{\left\vert A \right\vert}
(C) ∣A−1B−1∣\left\vert A^{-1}B^{-1} \right\vert(III) ∣A∣∣B∣\left\vert A \right\vert \left\vert B \right\vert
(D) ∣AB∣\left\vert AB \right\vert(IV) ∣A∣∣B∣\dfrac{\left\vert A \right\vert}{\left\vert B \right\vert}

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Use ∣XY∣=∣X∣∣Y∣|XY|=|X||Y| and ∣X−1∣=1∣X∣|X^{-1}|=\frac{1}{|X|}.

(A) ∣B∣∣A∣\frac{|B|}{|A|}, (II).

(B) ∣A∣∣B∣\frac{|A|}{|B|}, (IV).

(C) 1∣A∣∣B∣\frac{1}{|A||B|}, (I).

(D) ∣A∣∣B∣|A||B|, (III).

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