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If A is square matrix of order 3 x 3 such that aij=j−ia_{ij} = j - i, then which of the following statements are correct?

(A) A is a symmetric matrix.

(B) A is a skew symmetric matrix.

(C) ∣A∣=0|A| = 0.

(D) A is a diagonal matrix.

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

aij=j−ia_{ij}=j-i gives A=[012−101−2−10]A=\begin{bmatrix}0&1&2\\-1&0&1\\-2&-1&0\end{bmatrix}.

Since aji=i−j=−aija_{ji}=i-j=-a_{ij}, the matrix is skew-symmetric, so (B) is true and (A), (D) are false.

A skew-symmetric matrix of odd order has determinant 0, so (C) is true.

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