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The particular solution of the differential equation sec⁡2xtan⁡y dx−sec⁡2ytan⁡x dy=0\sec^2x\tan y\,dx - \sec^2y\tan x\,dy = 0, y=π4y=\frac{\pi}{4} when x=π4x=\frac{\pi}{4}, is

Solution

✅ Correct Option: 4

Separating variables, sec⁡2xtan⁡xdx=sec⁡2ytan⁡ydy\frac{\sec^2x}{\tan x}dx=\frac{\sec^2y}{\tan y}dy.

Integrating gives log⁡∣tan⁡x∣=log⁡∣tan⁡y∣+log⁡C\log|\tan x|=\log|\tan y|+\log C, so tan⁡x=Ctan⁡y\tan x=C\tan y.

At x=y=π4x=y=\frac{\pi}{4} both tangents are 1, so C=1C=1 and tan⁡y=tan⁡x\tan y=\tan x.

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