The particular solution of the differential equation ^2x y dx - ^2y x dy = 0, y=/4 when x=/4, is Option 1: x y=1 Option 2: x y=-1 Option 3: xy=- x Option 4: y= x

The answer is 'y= x'. View full solution:

CUET Mathematics - The particular solution of the differential equation ^2x y dx - ^2y x dy = 0, y=/4 when x=/4, is | PYQs + Solutions

CUET Mathematics 2026 30th May Shift 2

Calculus

Medium

core

$\tan x\tan y=1$

$\tan x\tan y=-1$

$\tan xy=-\tan x$

$\tan y=\tan x$

✅ Correct Option: 4

Related questions:

15 June Shift 2

The solution of the differential equation $\frac{dy}{dx} = \frac{6}{x^2}$ ; $y(1) = 3$ is :

30 May Shift 1

For the differential equation $ydx - (x + 3y^2)dy = 0$ , which of the following statements are true?

(A) It is a linear differential equation

(B) It is a homogenous differential equation

(D) If $y(0) = 1$ , then its particular solution is $x = 3y^2 - 1$

Choose the correct answer from the options given below:

21st May Shift 2

Match the LIST-I with LIST-II

LIST-I (Differential Equation)		LIST-II (Degree of Differential Equation)
A. $\dfrac{d^3y}{dx^3} + \left(\dfrac{d^2y}{dx^2}\right)^2 - \dfrac{dy}{dx} + y = 0$		I. 2
B. $\dfrac{dy}{dx} + \left(\dfrac{d^2y}{dx^2}\right)^4 + 2\left(\dfrac{d^3y}{dx^3}\right)^3 = 0$		II. 4
C. $\left(\dfrac{d^3y}{dx^3}\right)^2 + \left(\dfrac{d^2y}{dx^2}\right)^4 - y = 0$		III. 1
D. $\left(\dfrac{d^2y}{dx^2}\right)^4 + \left(\dfrac{dy}{dx}\right)^3 + y = 0$		IV. 3

Choose the correct answer from the options given below: