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The solution of differential equation x+1−x−1dydx=0\sqrt{x+1} - \sqrt{x-1}\frac{dy}{dx} = 0 is

Solution

✅ Correct Option: 1

Rearranging: dy=x+1x−1dx=x+1x2−1dxdy = \frac{\sqrt{x+1}}{\sqrt{x-1}} dx = \frac{x+1}{\sqrt{x^2-1}} dx. Integrating: y=∫xx2−1dx+∫dxx2−1y = \int \frac{x}{\sqrt{x^2-1}} dx + \int \frac{dx}{\sqrt{x^2-1}}. The first integral gives x2−1\sqrt{x^2-1} and the second gives log⁡∣x+x2−1∣\log|x+\sqrt{x^2-1}|. Therefore y=x2−1+log⁡∣x+x2−1∣+Cy = \sqrt{x^2-1} + \log|x + \sqrt{x^2-1}| + C.

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