For the system of equations AX = B, which of the following is correct?
For the system of equations AX = B, which of the following is correct?
Solution
For the system of equations :
A non-singular matrix has determinant and an inverse exists.
A singular matrix has determinant and no inverse exists.
When is non-singular, the system has a unique solution.
Since exists, multiply both sides by :
This gives exactly one solution.
When is singular, the system cannot have a unique solution.
Since does not exist, the system may have either infinitely many solutions or no solution at all, depending on .
Checking Statement 1: "If is singular, then has a unique solution."
This is incorrect. A singular matrix cannot produce a unique solution.
Checking Statement 2: "If is non-singular, then has infinitely many solutions."
This is incorrect. A non-singular matrix produces exactly one solution , not infinitely many.
Checking Statement 3: "If is non-singular, then has a unique solution."
This is correct. When is non-singular, gives a unique solution.
Checking Statement 4: "If is singular, then is always consistent."
This is incorrect. A singular matrix does not guarantee consistency; the system may have no solution depending on .
Therefore, the correct answer is Option 3.
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