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∫ex(1+x)dxcos⁡2(exx)\int \frac{e^x(1 + x)dx}{\cos^2(e^x x)} is equal to

Solution

✅ Correct Option: 4

The integral is: ∫ex(1+x)dxcos⁡2(exx)\int \frac{e^x(1 + x)dx}{\cos^2(e^x x)}

Notice that xexxe^x appears in the denominator inside cos⁡2(xex)\cos^2(xe^x).


Let u=xexu = xe^x

Using the product rule:

dudx=ex+xex\frac{du}{dx} = e^x + xe^x

dudx=ex(1+x)\frac{du}{dx} = e^x(1 + x)

du=ex(1+x)dxdu = e^x(1 + x)dx


The integral becomes:

∫ducos⁡2(u)\int \frac{du}{\cos^2(u)}

=∫sec⁡2(u)du= \int \sec^2(u)du

=tan⁡(u)+c= \tan(u) + c


Substituting u=xexu = xe^x:

tan⁡(xex)+c\tan(xe^x) + c

where cc is the constant of integration.

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