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If A is a square matrix of order 3 such that ∣A∣=3|A| = 3, then ∣adj(adjA)∣|adj(adj A)| is equal to:

Solution

✅ Correct Option: 4

Given: A is a square matrix of order 3 and ∣A∣=3|A| = 3

For any square matrix M of order n:

∣adj(M)∣=∣M∣n−1|adj(M)| = |M|^{n-1}


Since A is of order n=3n = 3:

∣adj(A)∣=∣A∣n−1|adj(A)| = |A|^{n-1}

∣adj(A)∣=∣A∣3−1|adj(A)| = |A|^{3-1}

∣adj(A)∣=∣A∣2|adj(A)| = |A|^2

∣adj(A)∣=(3)2|adj(A)| = (3)^2

∣adj(A)∣=9|adj(A)| = 9


Let B=adj(A)B = adj(A), so ∣B∣=9|B| = 9

Finding ∣adj(adjA)∣=∣adj(B)∣|adj(adj A)| = |adj(B)|:

∣adj(B)∣=∣B∣n−1|adj(B)| = |B|^{n-1}

∣adj(B)∣=∣B∣3−1|adj(B)| = |B|^{3-1}

∣adj(B)∣=∣B∣2|adj(B)| = |B|^2

∣adj(B)∣=(9)2|adj(B)| = (9)^2

∣adj(B)∣=81|adj(B)| = 81


Therefore, ∣adj(adjA)∣=81|adj(adj A)| = 81

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