CUET Mathematics - Let A be any square matrix of order 3 and B = bmatrix 0 & -4 & 2 \\ 4 & 0 & 3 \\ -2 & -3 & 0 bmatrix. Then the matrix ABA^T is a | PYQs + Solutions

CUET Mathematics 2025 14 May Shift 2

Algebra

Medium

common

Symmetric matrix

Skew symmetric matrix

Null matrix

Diagonal matrix

✅ Correct Option: 2

Related questions:

30 May Shift 1

If $A$ and $B$ are invertible matrices of order $3$ then match List-I with List-II

List-I	List-II
(A) $\text{adj}(A)$	(I) $B^{-1} A^{-1}$
(B) $(AB)^{-1}$	(II) $\|A\|^{-1}$
(C) $\|A^{-1}\|$	(III) $\|A\|^2$
(D) $\|\text{adj} A\|$	(IV) $\|A\|A^{-1}$

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15 May Shift 2

Match List-I with List-II

List-I	List-II
(Matrix A)	(Determinant of adj A)
(A) $\begin{bmatrix} 2 & 1 \\ 0 & -1 \end{bmatrix}$	(I) 6
(B) $\begin{bmatrix} 0 & 1 \\ 4 & -1 \end{bmatrix}$	(II) 5
(C) $\begin{bmatrix} 1 & 2 \\ -3 & -1 \end{bmatrix}$	(III) -4
(D) $\begin{bmatrix} 4 & -2 \\ 3 & 0 \end{bmatrix}$	(IV) -2

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21 May Shift 1

If $\begin{vmatrix} 1+a & 1 & 1 \\ 1 & 1+b & 1 \\ 1 & 1 & 1+c \end{vmatrix}$ , where a, b and c are non zero constants, then the value of $\frac{1}{a} + \frac{1}{b} + \frac{1}{c}$ is

CUET Mathematics 2025 14 May Shift 2 PYQs

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