CUET Mathematics - Match List-I with List-II $array|l|l| 0pt2.8exList-I & List-II \\[1.2ex] 0pt2.8ex(A) The minimum value of f(x) = (2x - 1)^2 + 3 & (I) 4 \\[1.2ex] 0pt2.8ex(B) The maximum value of f(x) = -|x + 1| + 4 & (II) 10 \\[1.2ex] 0pt2.8ex(C) The minimum value of f(x) = (2x) + 6 & (III) 3 \\[1.2ex] 0pt2.8ex(D) The maximum value of f(x) = -(x - 1)^2 + 10 & (IV) 5 \\[1.2ex] array$ Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2025 14 May Shift 1

Calculus

Medium

core

(A) - (I), (B) - (II), (C) - (III), (D) - (IV)

(A) - (III), (B) - (II), (C) - (I), (D) - (IV)

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

✅ Correct Option: 3

CUET Mathematics 2025 14 May Shift 1 PYQs