_/6^/3 tan x/tan x + cot x dx is equal to Option 1: /4 Option 2: 0 Option 3: /6 Option 4: /12

The answer is '/12'. View full solution:

Calculus > Integrals

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$\int_{\pi/6}^{\pi/3} \frac{tan x}{tan x + cot x} dx$ is equal to

$\frac{\pi}{4}$

$\frac{\pi}{6}$

$\frac{\pi}{12}$

✅ Correct Option: 4

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