The integral I = e^5_e x - e^4_e xe^3_e x - e^2_e x dx is equal to Option 1: x/2 + C, where C is the constant of integration Option 2: x^2/2 + C, where C is the constant of integration Option 3: x^3/3 + C, where C is the constant of integration Option 4: x^4/4 + C, where C is the constant of integration

The answer is 'x^3/3 + C, where C is the constant of integration'. View full solution:

Calculus > Integrals

Medium

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The integral I = $\int \frac{e^{5\log_e x} - e^{4\log_e x}}{e^{3\log_e x} - e^{2\log_e x}} dx$ is equal to

$\frac{x}{2} + C$ , where C is the constant of integration

$\frac{x^2}{2} + C$ , where C is the constant of integration

$\frac{x^3}{3} + C$ , where C is the constant of integration

$\frac{x^4}{4} + C$ , where C is the constant of integration

✅ Correct Option: 3

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The integral I = $\int \frac{e^{5\log_e x} - e^{4\log_e x}}{e^{3\log_e x} - e^{2\log_e x}} dx$ is equal to

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