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If A and B are invertible matrices then which of the following statement is NOT correct?

Solution

✅ Correct Option: 2

For invertible matrices A and B, examining each statement:

Option 1: adj A = |A|A⁻¹

The relationship between inverse and adjoint is:

A−1=adj A∣A∣A^{-1} = \frac{\text{adj A}}{|A|}

Multiplying both sides by |A|:

adj A=∣A∣A−1\text{adj A} = |A|A^{-1}

This statement is correct.


Option 2: (A+B)−1=A−1+B−1(A + B)^{-1} = A^{-1} + B^{-1}

The inverse does not distribute over addition.

Counterexample using A=[2]A = [2] and B=[3]B = [3]:

A+B=[5]A + B = [5]

(A+B)−1=[1/5]=0.2(A + B)^{-1} = [1/5] = 0.2

However:

A−1+B−1=[1/2]+[1/3]=0.5+0.333...=0.833...A^{-1} + B^{-1} = [1/2] + [1/3] = 0.5 + 0.333... = 0.833...

Since 0.2≠0.8330.2 \neq 0.833, this statement is NOT correct.


Option 3: ∣A−1∣=∣A∣−1|A^{-1}| = |A|^{-1}

From the identity A×A−1=IA \times A^{-1} = I:

∣A×A−1∣=∣I∣|A \times A^{-1}| = |I|

∣A∣×∣A−1∣=1|A| \times |A^{-1}| = 1

∣A−1∣=1∣A∣=∣A∣−1|A^{-1}| = \frac{1}{|A|} = |A|^{-1}

This statement is correct.


Option 4: (AB)−1=B−1A−1(AB)^{-1} = B^{-1}A^{-1}

Verification:

(AB)×(B−1A−1)=A(BB−1)A−1(AB) \times (B^{-1}A^{-1}) = A(BB^{-1})A^{-1}

=AIA−1= AIA^{-1}

=AA−1= AA^{-1}

=I= I

This statement is correct.


Therefore, Option 2 is NOT correct.

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