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If [5x+87y+310x+12]=[23y+150]\begin{bmatrix} 5x + 8 & 7 \\ y + 3 & 10x + 12 \end{bmatrix} = \begin{bmatrix} 2 & 3y + 1 \\ 5 & 0 \end{bmatrix}, then the value of 5x+3y5x + 3y is equal to :

Solution

✅ Correct Option: 4

When two matrices are equal, their corresponding entries (same row, same column) must be equal.

[5x+87y+310x+12]=[23y+150]\begin{bmatrix} 5x + 8 & 7 \\ y + 3 & 10x + 12 \end{bmatrix} = \begin{bmatrix} 2 & 3y + 1 \\ 5 & 0 \end{bmatrix}

This gives us four equations:

5x+8=2⋯(1)5x + 8 = 2 \quad\cdots(1)

7=3y+1⋯(2)7 = 3y + 1 \quad\cdots(2)

y+3=5⋯(3)y + 3 = 5 \quad\cdots(3)

10x+12=0⋯(4)10x + 12 = 0 \quad\cdots(4)


From equation (1)(1):

5x+8=25x + 8 = 2

5x=−65x = -6

x=−65x = -\dfrac{6}{5}

Verifying with equation (4)(4):

10(−65)+12=−12+12=0  ✓10\left(-\dfrac{6}{5}\right) + 12 = -12 + 12 = 0 \;\checkmark


From equation (3)(3):

y+3=5y + 3 = 5

y=2y = 2

Verifying with equation (2)(2):

3(2)+1=7  ✓3(2) + 1 = 7 \;\checkmark


Now substituting x=−65x = -\dfrac{6}{5} and y=2y = 2 into 5x+3y5x + 3y:

5x+3y=5(−65)+3(2)5x + 3y = 5\left(-\dfrac{6}{5}\right) + 3(2)

=−6+6= -6 + 6

=0= \boxed{0}

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