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If C is an arbitrary constant, then

Match the LIST-I with LIST-II

LIST-ILIST-II
A.∫ax dx\displaystyle\int a^x \, dxI.sin⁡−1xa+C\sin^{-1}\dfrac{x}{a} + C
B.∫dxa2−x2\displaystyle\int \dfrac{dx}{\sqrt{a^2 - x^2}}II.log⁡e∣x+x2−a2∣+C\log_e \vert x + \sqrt{x^2 - a^2} \vert + C
C.∫dxa2+x2\displaystyle\int \dfrac{dx}{\sqrt{a^2 + x^2}}III.axlog⁡ea+C\dfrac{a^x}{\log_e a} + C
D.∫dxx2−a2\displaystyle\int \dfrac{dx}{\sqrt{x^2 - a^2}}IV.log⁡e∣x+a2+x2∣+C\log_e \vert x + \sqrt{a^2 + x^2} \vert + C

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

These are standard forms: ∫axdx=axlog⁡ea+C\int a^xdx=\frac{a^x}{\log_e a}+C (III); ∫dxa2−x2=sin⁡−1xa+C\int\frac{dx}{\sqrt{a^2-x^2}}=\sin^{-1}\frac{x}{a}+C (I); ∫dxa2+x2=log⁡e∣x+a2+x2∣+C\int\frac{dx}{\sqrt{a^2+x^2}}=\log_e|x+\sqrt{a^2+x^2}|+C (IV); ∫dxx2−a2=log⁡e∣x+x2−a2∣+C\int\frac{dx}{\sqrt{x^2-a^2}}=\log_e|x+\sqrt{x^2-a^2}|+C (II).

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