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If ∣−a2abacba−b2bcacbc−c2∣=4x\begin{vmatrix} -a^2 & ab & ac \\ ba & -b^2 & bc \\ ac & bc & -c^2 \end{vmatrix} = 4x, then x=x =

Solution

✅ Correct Option: 2

Factor a, b, c from columns 1, 2, 3 of the determinant, then a, b, c from rows 1, 2, 3 to get a2b2c2∣−1111−1111−1∣a^2 b^2 c^2 \begin{vmatrix} -1 & 1 & 1 \\ 1 & -1 & 1 \\ 1 & 1 & -1 \end{vmatrix}. Expanding the simple determinant gives 4. So determinant =4a2b2c2=4x= 4 a^2 b^2 c^2 = 4x, giving x=a2b2c2x = a^2 b^2 c^2.

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