Let a = 2i + 3j - 4k and b = 3i - 5j + 6k. Let c be a vector such that c x a = b x c and c*(2a-3b) = 238sqrt(2) then |c|^2 is equal to : Option 1: 112 Option 2: 164 Option 3: 264 Option 4: 260

The answer is '264'. View full solution:

CUET Mathematics - Let a = 2i + 3j - 4k and b = 3i - 5j + 6k. Let c be a vector such that c x a = b x c and c*(2a-3b) = 238sqrt(2) then |c|^2 is equal to : | PYQs + Solutions

CUET Mathematics 2022 17 Aug Shift 2

Algebra

Hard

112

164

264

260

✅ Correct Option: 3

Related questions:

16 July Shift 2

If $\vec{a} = \hat{i} - \hat{j} + \hat{k}$ , $\vec{b} = 2\hat{i} + \hat{j} - 3\hat{k}$ , $\vec{c} = 2\hat{i} - \hat{j} + 7\hat{k}$ and $\vec{a} \times (\vec{b} \times \vec{c}) = \lambda \vec{b} + \mu \vec{c}$

(When $\lambda$ , $\mu$ are scalars), then the value of $\lambda + \mu$ is:

23 Aug Shift 1

If $-3 \leq k \leq 1$ and $|\vec{a}| = 2$ then $|k\vec{a}|$ is

3 June Shift 2

Let $\theta$ be the angle between two vectors $\vec{a}$ and $\vec{b}$ . Then match List-I with List-II

List-I	List-II
(A) $\sin \theta$	(I) $\dfrac{\vec{a} \cdot \vec{b}}{\vert \vec{a}\vert \vert \vec{b}\vert }$
(B) $\cos \theta$	(II) $\vert \vec{a} \times \vec{b}\vert$
(C) Area of the parallelogram with adjacent sides represented by $\vec{a}$ and $\vec{b}$	(III) $\dfrac{\vec{a} \cdot \vec{b}}{\vert \vec{a}\vert }$
(D) Projection of $\vec{a}$ on $\vec{b}$	(IV) $\dfrac{\vert \vec{a} \times \vec{b}\vert }{\vert \vec{a}\vert \vert \vec{b}\vert }$

Choose the correct answer from the options given below:

CUET Mathematics 2022 17 Aug Shift 2 PYQs

Keyboard Shortcuts