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If x−y=2x-y=2 and y−z=3y-z=3 then value of ∣1xx21yy21zz2∣=\begin{vmatrix}1 & x & x^2 \\ 1 & y & y^2 \\ 1 & z & z^2\end{vmatrix} =

Solution

✅ Correct Option: 4

This is a Vandermonde determinant: (y−x)(z−x)(z−y)=(−2)(−5)(−3)=−30(y-x)(z-x)(z-y) = (-2)(-5)(-3) = -30.

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